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Table 1 Comparison of sociodemographic characteristics of children with Apelin hormone levels and scale total score (N = 151)

From: Salivary apelin hormone response and dysfunctional attitudes in adolescents in Türkiye: a relational screening model

Variables

N (%)

Apelin hormone levels

Scale total score

Gender

   

Girl

69(45.7)

0.696 ± 0.052

52.95 ± 14.43

Boy

82(54.3)

0.671 ± 0.047

59.04 ± 14.22

  

t = 3.101

t=-2.790

  

p=.002*

p=.006*

Age

   

9-101

50(33.1)

0.647 ± 0.044

67.52 ± 12.25

11–122

49(32.5)

0.690 ± 0.034

54.87 ± 8.46

13–143

52(34.4)

0.710 ± 0.051

46.75 ± 10.92

  

F = 26.809a

F = 48.814b

  

p=.000**

p=.000**

Perception of income status

   

Low

11(7.3)

0.689 ± 0.057

56.63 ± 15.44

Medium

125(82.8)

0.683 ± 0.051

55.45 ± 13.55

High

15(9.9)

0.674 ± 0.039

62.73 ± 12.37

  

F = 0.310

F = 1.927

  

p =.734

p =.149

Mother’s education level

   

Primary school

58(38.4)

0.691 ± 0.048

55.12 ± 13.34

Middle school

40(26.5)

0.678 ± 0.054

57.75 ± 14.57

High school

42(27.8)

0.675 ± 0.052

56.59 ± 13.74

University and above

11(7.3)

0.684 ± 0.047

F = 0.891

55.63 ± 12.88

F = 0.305

  

p =.448

p =.822

Mother’s occupation

   

Housewife

128(84.8)

0.684 ± 0.052

56.77 ± 13.98

Civil servant/worker

13(8.6)

0.675 ± 0.038

56.23 ± 8.63

Retired/other

10(6.6)

0.675 ± 0.056

49.80 ± 14.21

  

F = 0.300

F = 1.211

  

p =.742

p =.301

Father’s education level

   

Primary school

30(19.9)

0.688 ± 0.040

54.40 ± 12.77

Middle school

32(21.2)

0.666 ± 0.056

61.43 ± 14.91

High school

63(41.7)

0.691 ± 0.050

54.61 ± 12.53

University and above

26(17.2)

0.675 ± 0.053

F = 2.098

56.03 ± 14.84

F = 2.064

  

p =.103

p =.108

Father’s occupation

   

Tradesman

26(17.2)

0.680 ± 0.041

57.11 ± 10.86

Civil Servant

32(21.2)

0.684 ± 0.047

54.03 ± 12.78

Laborer

44(29.1)

0.675 ± 0.049

59.02 ± 13.31

Retired/other

49(32.5)

0.689 ± 0.059

F = 0.600

54.79 ± 15.64

F = 1.107

  

p =.616

p =.348

  1. *Independent T test **One-Way ANOVA aBonferroni= 3 > 1, 2 > 1 bBonferroni= 1 > 2, 1 > 3, 2 > 3